FREE BOOKS

Author's List




PREV.   NEXT  
|<   134   135   136   137   138   139   140   141   142   143   144   145   146   147   148   149   150   151   152   153   154   155   156   157   158  
159   160   161   162   163   164   165   166   167   168   169   170   171   172   173   174   175   176   177   178   179   180   181   182   183   >>   >|  
nous. The qualification "If the arc of swing is small" is introduced because, as was discovered by Christiaan Huygens, the arc of vibration of a truly isochronous pendulum should not be a circle with centre O, but a cycloid DM, generated by the rolling of a circle with diameter DQ = 1/2OD, upon a straight line QM. However, for a short distance near the bottom, the circle so nearly coincides with the cycloid that a pendulum swinging in the usual circular path is, for small arcs, isochronous for practical purposes. [Illustration: FIG. 6.] The formula representing the time of oscillation of a pendulum, in a circular arc, is thus found:--Let OB (fig. 6) be the pendulum, B be the position from which the bob is let go, and P be its position at some period during its swing. Put FC = h, and MC = x, and OB = l. Now when a body is allowed to move under the force of gravity in any path from a height h, the velocity it attains is the same as a body would attain falling freely vertically through the distance h. Whence if v be the velocity of the bob at P, v = sqrt(2gFM) = sqrt(2g(h - x)). Let Pp = ds, and the vertical distance of p below P = dx, then Pp = velocity at P X dt; that is, dt = ds/v. ds l l Also -- = -- = ---------------, dx MP sqrt(x(2l - x)) ds ldx 1 whence dt = -- = --------------- . --------------- v sqrt(x(2l - x)) sqrt(2g(h - x)) 1 / l dx 1 = --- / --- . -------------- . ---------------- 2 \/ g sqrt(x(p - x)) sqrt(1 - (x/2l)) Expanding the second part we have 1 / l dx / x \ dt = --- / --- . -------------- . ( 1 + --- + ... ). 2 \/ g sqrt(x(h - x)) \ 4l / If this is integrated between the limits of 0 and h, we have / l / h \ t = [pi] / --- . ( 1 + --- + ... ), \/ g \ 8l / where t is the time of swing from B to A. The terms after the second may be neglected. The first term, [pi] sqrt(l/g), is the time of swing in a cycloid. The second part represents the addition necessary if the swing is circular and not cycloidal, and therefore expresses the "circular error." Now h = BC^2/l = 2[pi]^2[theta]^2l / 360^2, where [theta] is half the angle
PREV.   NEXT  
|<   134   135   136   137   138   139   140   141   142   143   144   145   146   147   148   149   150   151   152   153   154   155   156   157   158  
159   160   161   162   163   164   165   166   167   168   169   170   171   172   173   174   175   176   177   178   179   180   181   182   183   >>   >|  



Top keywords:
circular
 

pendulum

 

distance

 
cycloid
 
velocity
 
circle
 

position

 

isochronous

 

vertical


expresses

 
cycloidal
 
introduced
 

Whence

 

vertically

 

freely

 

discovered

 

falling

 

limits


integrated

 

addition

 
represents
 

qualification

 

Expanding

 
neglected
 

swinging

 
coincides
 
bottom

practical

 

representing

 

oscillation

 

formula

 

purposes

 
Illustration
 
centre
 

diameter

 
generated

rolling

 

straight

 

However

 

allowed

 

Christiaan

 

gravity

 
attains
 

height

 
Huygens

vibration
 

period

 

attain