FREE BOOKS

Author's List




PREV.   NEXT  
|<   81   82   83   84   85   86   87   88   89   90   91   92   93   94   95   96   97   98   99   100   101   102   103   104   105  
106   107   108   109   110   111   112   113   114   115   116   117   118   119   120   121   122   123   124   125   126   127   128   129   130   >>   >|  
l^{-} + H_{2}O + 13,700 cal. K^{+}, OH^{-} + H^{+}, NO_{3}^{-} = K^{+}, NO_{3}^{-} + H_{2}O + 13,700 cal. Ca^{++}, (OH)_{2}^{--} + H_{2}^{++}, SO_{4}^{--} = Ca^{++}, SO_{4}^{--} + 2H_{2}O + 2 x 13,700 cal. ~Neutralization a quantitative act.~ Since neutralization is a definite chemical act, each acid will require a perfectly definite weight of each base for its neutralization. For example, a given weight of sulphuric acid will always require a definite weight of sodium hydroxide, in accordance with the equation H_{2}, SO_{4} + 2Na, OH = Na_{2}, SO_{4} + 2H_{2}O. ~Determination of the ratio in neutralization.~ The quantities of acid and base required in neutralization may be determined in the following way. Dilute solutions of the two substances are prepared, the sulphuric acid being placed in one of the burettes (Fig. 34) and the sodium hydroxide in the other. The levels of the two liquids are then brought to the zero marks of the burettes by means of the stopcocks. A measured volume of the acid is drawn off into a beaker, a few drops of litmus solution added, and the sodium hydroxide is run in drop by drop until the red litmus just turns blue. The volume of the sodium hydroxide consumed is then noted. If the concentrations of the two solutions are known, it is easy to calculate what weight of sodium hydroxide is required to neutralize a given weight of sulphuric acid. By evaporating the neutralized solution to dryness, the weight of the sodium sulphate formed can be determined directly. Experiment shows that the weights are always in accordance with the equation in the preceding paragraph. [Illustration: Fig. 34] ~Extent of dissociation.~ The question will naturally arise, When an acid, base, or salt dissolves in water, do all the molecules dissociate into ions, or only a part of them? The experiments by which this question can be answered cannot be described here. It has been found, however, that only a fraction of the molecules dissociate. The percentage which will dissociate in a given case depends upon several conditions, the chief of which are: (1) The concentration of the solution. In concentrated solutions only a very small percentage of dissociation occurs. As the solution is diluted the percentage increases, and in very dilute solutions it may be very large, though it is never
PREV.   NEXT  
|<   81   82   83   84   85   86   87   88   89   90   91   92   93   94   95   96   97   98   99   100   101   102   103   104   105  
106   107   108   109   110   111   112   113   114   115   116   117   118   119   120   121   122   123   124   125   126   127   128   129   130   >>   >|  



Top keywords:

weight

 

sodium

 

hydroxide

 
solution
 
neutralization
 

solutions

 

sulphuric

 

dissociate

 

definite

 

percentage


determined

 

burettes

 

dissociation

 
question
 
molecules
 

volume

 
litmus
 

required

 

accordance

 
equation

require

 

experiments

 

Extent

 

quantitative

 

Illustration

 

paragraph

 
weights
 

preceding

 

Neutralization

 
naturally

answered

 

dissolves

 
occurs
 

concentrated

 
concentration
 

diluted

 

dilute

 

increases

 

fraction

 

conditions


depends

 

formed

 

brought

 

stopcocks

 

measured

 
liquids
 
levels
 

Dilute

 

Determination

 
substances