| 1724 | 1854 | 2019 | 4687
II. | 398 | 409 | 430 | 463 | 504 | 1171
III. | --- | 0 | 1 | 2 | 4 | 30
IV. | --- | 0 | 0 | 0 | 1 | 7
V. | 1991 | 2047 | 2153 | 2315 | 2520 | 5835
VI. | 3 | 3 | 4 | 5 | 0 | 4
VII. | 4 | 4 | 3 | 2 | 7 | 3
VIII. | 16 | 4 | 14 | 11 | 5 | 13
IX. | --- | --- | 0 | 0 | 0 | 1
X. | 0 | 0 | 0 | 1 | 1 | 10
XI. | 16 | 4 | 24 | 21 | 15 | 13
XII. | 16 | 4 | 23 | 20 | 13 |0 say 30
XIII. | 29 | 41 | 22 | 25 | 32 | 45
XIV. | 4 | 2 | 4 | 7 | 7 | 6
XV. | 29 | 43 | 28 | 27 | 32 | 49
Easter Day |Mar.29|Apr.12|Mar.28|Mar.27|Apr.1 | Apr.18
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13. _Rule for determining Easter Day of the Antegregorian Calendar in any
year of the old style._ To the several parts of the rule are annexed, by
way of example, the results for the year 1287. The steps are numbered to
correspond with the steps of the Gregorian rule, so that it can be seen
what augmentations the latter requires.

I. Set down the given year. (1287).

II. Take the quotient of the given year divided by 4, neglecting the
remainder (321).

V. Take 4 more than the sum of I. and II. (1612).

VI. Find the remainder of V. divided by 7. (2).

VII. Subtract VI. from 7; this is the number of the dominical letter

1 2 3 4 5 6 7 (5; dominical letter E).
A B C D E F G

VIII. Divide one more than the given year by 19, the remainder (or 19 if no
remainder) is the golden number. (15).

XII. Divide 3 less than 11 times VIII. by 30; the remainder (or 30 if there
be no remainder) is the epact. (12).

{368}

_When the Epact is 23, or less._

XIII. Subtract XII., the epact, from 45. (33).

XIV. Subtract the epact from 27, divide by 7, and keep the remainder, or 7,
if there be no remainder, (1).

_When the Epact is greater than 23._

XIII. Subtract XII., the epact, from 75.

XIV. Subtract the epact from 57, divide by 7, and keep the remainder, or 7,
if there be no remainder.

XV. To XIII. add VII., the dominical number, (and 7 besides if XIV. be
greater than VII.,) and subtract XIV., the result is the day of March, or
if more than 31, subtract 31, and the r