FREE BOOKS

Author's List




PREV.   NEXT  
|<   38   39   40   41   42   43   44   45   46   47   48   49   50   51   52   53   54   55   56   57   58   59   60   61   62  
63   64   65   66   67   68   69   70   71   72   73   74   75   76   77   78   79   80   81   82   83   84   85   86   87   >>   >|  
ngents to the circles are equal is a straight line. Consider the case of two circles, and in the first place suppose them to intersect in two real points A and B. Then by Euclid iii. 36 it is seen that the line joining the points A and B is the locus of the intersection of equal tangents, for if P be any point on AB and PC and PD the tangents to the circles, then PA.PB = PC squared = PD squared, and therefore PC = PD. Furthermore it is seen that AB is perpendicular to the line joining the centres, and divides it in the ratio of the squares of the radii. The line AB is termed the "radical axis." A system coaxal with the two given circles is readily constructed by describing circles through the common points on the radical axis and any third point; the minimum circle of the system is obviously that which has the common chord of intersection for diameter, the maximum is the radical axis--considered as a circle of infinite radius. In the case of two non-intersecting circles it may be shown that the radical axis has the same metrical relations to the line of centres. [Illustration: Fig. 5] There are several methods of constructing the radical axis in this case. One of the simplest is: Let P and P' (fig. 5) be the points of contact of a common tangent; drop perpendiculars PL, P'L', from P and P' to OO', the line joining the centres, then the radical axis bisects LL' (at X) and is perpendicular to OO'. To prove this let AB, AB1 be the tangents from any point on the line AX. Then by Euc. i. 47, AB squared = AO squared - OB squared = AX squared + OX squared + OP squared; and OX squared = OD squared - DX squared = OP squared + PD squared - DX squared. Therefore AB squared = AX squared - DX squared + PD squared. Similarly AB' squared = AX squared - DX squared + DP' squared. Since PD = PD', it follows that AB = AB'. To construct circles coaxal with the two given circles, draw the tangent, say XR, from X, the point where the radical axis intersects the line of centres, to one of the given circles, and with centre X and radius XR describe a circle. Then circles having the intersections of tangents to this circle and the line of centres for centres, and the lengths of the tangents as radii, are members of the coaxal system. In the case of non-intersecting circles, it is seen that the minimum circles of the coaxal system are a pair of points I and I', where the orthogonal circle to the system inter
PREV.   NEXT  
|<   38   39   40   41   42   43   44   45   46   47   48   49   50   51   52   53   54   55   56   57   58   59   60   61   62  
63   64   65   66   67   68   69   70   71   72   73   74   75   76   77   78   79   80   81   82   83   84   85   86   87   >>   >|  



Top keywords:

squared

 

circles

 

radical

 

centres

 

points

 
system
 

circle

 

tangents

 
coaxal
 

common


joining

 

radius

 

intersecting

 
minimum
 

intersection

 
perpendicular
 

tangent

 

perpendiculars

 
contact
 

bisects


describe

 

centre

 

intersects

 

intersections

 

lengths

 

orthogonal

 

members

 

Therefore

 
Similarly
 

construct


Furthermore

 
divides
 

termed

 

squares

 

Consider

 

straight

 

ngents

 

suppose

 

Euclid

 

intersect


readily

 

constructed

 

Illustration

 
relations
 

metrical

 

simplest

 
constructing
 
methods
 

describing

 

infinite