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red from the vertex, then 3 . . . tan i = 2y/x. Let the length of half the parabolic chain be called s, then 4 . . . s = x+2y squared/3x. The following is the approximate expression for the relation between a change [Delta]s in the length of the half chain and the corresponding change [Delta]y in the dip:-- s+[Delta]s = x+(2/3x) {y squared+2y[Delta]y+([Delta]y) squared} = x+2y squared/3x+4y[Delta]y/3x+2[Delta]y squared/3x, or, neglecting the last term, 5 . . . [Delta]s = 4y[Delta]y/3x, and 6 . . . [Delta]y = 3x[Delta]s/4y. From these equations the deflection produced by any given stress on the chains or by a change of temperature can be calculated. [Illustration: FIG. 71.] 36. _Deflection of Girders._-- Let fig. 71 represent a beam bent by external loads. Let the origin O be taken at the lowest point of the bent beam. Then the deviation y = DE of the neutral axis of the bent beam at any point D from the axis OX is given by the relation d squaredy M --- = -- , dx squared EI where M is the bending moment and I the amount of inertia of the beam at D, and E is the coefficient of elasticity. It is usually accurate enough in deflection calculations to take for I the moment of inertia at the centre of the beam and to consider it constant for the length of the beam. Then dy 1 -- = ---[Integral]Mdx dx EI 1 y = ---[Integral][Integral]Mdx squared. EI The integration can be performed when M is expressed in terms of x. Thus for a beam supported at the ends and loaded with w per inch length M = w(a squared-x squared), where a is the half span. Then the deflection at the centre is the value of y for x = a, and is 5 wa^4 [delta] = --- ----. 24 EI The radius of curvature of the beam at D is given by the relation R = EI/M. [Illustration: FIG. 72.] 37. _Graphic Method of finding Deflection._--Divide the span L into any convenient number n of equal parts of length l, so that nl = L; compute the radii of curvature R_1, R_2, R_3 for the several sections. Let measurements along the beam be represented according to any convenient scale, so that calling L_1 and l_1 the lengths to be drawn on paper, we have L = aL_1; now let r_1, r_2, r_3 be a series of radii such that r_1 = R_1/ab, r_2 = R_2/ab, &c., where b is any convenient constant chosen of such magnitude as will allow arcs with the radii, r_1, r_2, &c
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