FREE BOOKS

Author's List




PREV.   NEXT  
|<   49   50   51   52   53   54   55   56   57   58   59   60   61   62   63   64   65   66   67   68   69   70   71   72   73  
74   75   76   77   78   79   80   81   82   83   84   85   86   87   88   89   90   91   92   93   94   95   96   97   98   >>   >|  
small loss in heat. In an ordinary 16 candlepower carbon lamp, the resistance of this filament is 220 ohms. Therefore the amount of current that a 110-volt generator can force through that filament is 110/220, or 1/2 ampere. [Illustration: Armature and field coils of a direct current dynamo] One hundred lamps would provide 100 paths of 220 ohms resistance each to carry current, and the amount required to light 100 such lamps would be 100 x 1/2 or 50 amperes. Every electrical device--a lamp, a stove, an iron, a motor, etc.,--must, by regulations of the Fire Underwriters' Board be plainly marked with the voltage of the current for which it is designed and the amount of current it will consume. This is usually done by indicating its capacity in watts, which as we have seen, means volts times amperes, and from this one can figure ohms, by the above formulas. _A Short Circuit_ We said a few paragraphs back that under no conditions must two bare wires leading from electric mains be permitted to touch each other, without some form of resistance being interposed in the form of lamps, or other devices. Let us see what would happen if two such bare wires did touch each other. Our dynamo as we discover by reading its plate, is rated to deliver 50 amperes, let us say, at 110 volts pressure. Modern dynamos are rated liberally, and can stand 100% overload for short periods of time, without dangerous overheating. Let us say that the mains conveying current from the armature to the switchboard are five feet long, and of No. 2 B. & S. gauge copper wire, a size which will carry 50 amperes without heating appreciably. The resistance of this 10 feet of No. 2 copper wire, is, as we find by consulting a wire table, .001560 ohms. If we touch the ends of these two five-foot wires together, we instantly open a clear path for the flow of electric current, limited only by the carrying capacity of the wire and the back pressure of .001560 ohms resistance. Using Ohm's Law, C equals E divided by R, we find that C (amperes) equals 110/.001560 or _70,515 amperes_! [Illustration: A direct current dynamo] Unless this dynamo were properly protected, the effect of such a catastrophe would be immediate and probably irreparable. In effect, it would be suddenly exerting a force of nearly 10,000 horsepower against the little 10 horsepower water wheel that is driving this dynamo. The mildest thing that could happen would be to melt the feed-wir
PREV.   NEXT  
|<   49   50   51   52   53   54   55   56   57   58   59   60   61   62   63   64   65   66   67   68   69   70   71   72   73  
74   75   76   77   78   79   80   81   82   83   84   85   86   87   88   89   90   91   92   93   94   95   96   97   98   >>   >|  



Top keywords:

current

 

amperes

 

resistance

 

dynamo

 
amount
 

001560

 

capacity

 

copper

 

equals

 

electric


horsepower

 

Illustration

 

filament

 
happen
 
effect
 
pressure
 

direct

 

appreciably

 

liberally

 

consulting


heating

 

overload

 

armature

 
switchboard
 

conveying

 

overheating

 
periods
 
dangerous
 

suddenly

 
exerting

irreparable
 

properly

 
protected
 

catastrophe

 
mildest
 

driving

 

Unless

 
limited
 

instantly

 

carrying


divided

 
dynamos
 

conditions

 

device

 
electrical
 

regulations

 

voltage

 

designed

 
marked
 

plainly