FREE BOOKS

Author's List




PREV.   NEXT  
|<   47   48   49   50   51   52   53   54   55   56   57   58   59   60   61   62   63   64   65   66   67   68   69   70   71  
72   73   74   75   76   77   78   79   80   81   82   83   84   85   86   87   88   89   90   91   92   93   94   95   96   >>   >|  
c. The arc R'K' is a plus correction therefore, and the smaller arc RK a minus correction. If the moon is between her descending and ascending node, (taking now the node on the ecliptic,) the correction is negative, and we take the smaller arc. If the moon is between her ascending and descending node, the correction is positive, and we take the larger arc. If the moon is 90d from the node, the correction is a maximum. If the moon is at the node, the correction is null. In all other positions it is as the sine of the moon's distance from the nodes. We must now find the maximum value of these arcs of correction corresponding to the mean inclination of 2d 45'. To do this we may reduce TC to Tt in the ratio of radius to cosine of the inclination, and taking TS for radius. [Illustration: Fig. 9] {TC x Cos &c. (inclination 2d 45')}/R is equal the cosine of the arc SK' and SK' + AS = AK' and AK' + AR' = R'K'. But from the nature of the circle, arc RK + arc R'K' = angle RCK + angle R'CK', or equal to double the inclination; and therefore, by subtracting either arc from double the inclination, we may get the other arc. The maximum value of these arcs can, however, be found by a simple proportion, by saying; as the arc AR, plus the inclination, is to the inclination, so is the inclination to the difference between them; and therefore, the inclination, plus half the difference, is equal the greater arc, and the inclination, minus half the difference, is equal the lesser; the greater being positive, and the lesser negative. Having found the arc AR, and knowing the moon's distance from either node, we must reduce these values of the arcs RK and R'K' just found, in the ratio of radius to the sine of that distance, and apply it to the arc AR or A'R', and we shall get the first correction equal to the arc AK or AK'. Call the arc AR = a " inclination = n " distance from the node = d " arc AK = k and supposing the value of AK be wanted for the northern hemisphere when the moon is between her descending and ascending node, we have n^2 ------- a + n (n - ------- ) sin d. 2 k = a - ---------------------- R If the moon is between her ascending and descending node, then n^2 ------- a + n (n
PREV.   NEXT  
|<   47   48   49   50   51   52   53   54   55   56   57   58   59   60   61   62   63   64   65   66   67   68   69   70   71  
72   73   74   75   76   77   78   79   80   81   82   83   84   85   86   87   88   89   90   91   92   93   94   95   96   >>   >|  



Top keywords:

inclination

 

correction

 
descending
 

distance

 

ascending

 
maximum

radius

 

difference

 

lesser

 

double

 
cosine
 

greater


reduce
 

negative

 

taking

 

smaller

 

positive

 
knowing

values

 

Having

 

ecliptic

 
hemisphere
 

northern

 

wanted


supposing

 
proportion
 

circle

 
nature
 
positions
 

Illustration


simple
 

larger

 

subtracting