FREE BOOKS

Author's List




PREV.   NEXT  
|<   9   10   11   12   13   14   15   16   17   18   19   20   21   22   23   24   25   26   27   28   29   30   31   32   33  
34   35   36   37   >>  
a beam, of 12 feet span and 12 feet wide, to support a load of 22400 lbs. will be ------ -------------------- / 4WL / 4 X 22400 x 12 x 12 ------- d = / ------ = / ------------------- = / 215.04 = 15 in. nearly \/ 5000 b \/ 5000 x 12 \/ [TeX: $d = \sqrt\frac{4 WL}{5000 b}} = \sqrt\frac{4 \times 22400 \times 12 \times 12}{5000 \times 12} = \sqrt{215.04} = 15$] The following Table was calculated by the above rule--and the dimensions altered according to the actual practice of the writer. Span. Breadth. Depth. 4 10 12 6 10 12 8 12 12 10 12 13 12 12 15 16 12 18 18 12 20 20 12 22 These dimensions will give ample strength and stiffness. Fig. 1, Plate I. gives an illustration of this kind of bridge--in which a, a, are the bolsters or wall plates, shown in section, to which the bridge beams are notched and bolted. Fig. 1, A, Plate I, shows the method of diagonally bracing these beams by planks, dimensions of which in general use are 6 to 8 by 2 to 3 inches. The track should rest on ties, about 6 inches by 8 or 10 inches--the same bolt confining the ends of the ties and diagonal braces when practicable. These ties should be notched on the string pieces 2 or 3 inches--without cutting the stringers. Below is a table giving general dimensions, in inches, of the several parts of a bridge of this description. Span. Bolsters. Stringers. Ties. Braces. Diameter of Bolts. 4 12 x 12 10 x 12 6 x 8 2 x 8 1 inch. 10 12 x 12 12 x 13 6 x 8 2 x 8 1 " 16 14 x 14 12 x 18 6 x 8 2 x 8 1 " 20 14 x 14 12 x 22 6 x 8 2 x 8 1 " Each bolt must have a washer under the head, and also under the nut. For a span of from 15 to 30 feet, we can use the combination shown in Plate II, Fig. 3. The piece A F must have the same dimensions as a simple string piece of a length A B--so that it may not yield between B and either of the points A or D. The two braces D F and E F must be stiff enough to support the load coming upon them. Suppose the weight on a pair of drivers of a Locomotive to be 10 tons, then each side must bear 5 tons, and each brace 2-1/2 tons = 2-1/2 x 2240 = 5600 lbs. Now, to allow for sudden or extra strains, call 8000
PREV.   NEXT  
|<   9   10   11   12   13   14   15   16   17   18   19   20   21   22   23   24   25   26   27   28   29   30   31   32   33  
34   35   36   37   >>  



Top keywords:

inches

 

dimensions

 

bridge

 

general

 

braces

 

notched

 

string

 

support

 

sudden


simple

 
combination
 

length

 

washer

 
strains
 

Locomotive

 

drivers

 

weight

 

Suppose


points
 

coming

 

bolted

 

altered

 
actual
 

section

 

method

 
calculated
 

planks


diagonally

 

bracing

 

plates

 
stiffness
 

strength

 
illustration
 
bolsters
 

practice

 

writer


Breadth

 

giving

 

cutting

 

stringers

 
Braces
 

Diameter

 

Stringers

 

description

 
Bolsters

pieces

 

confining

 

practicable

 

diagonal